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Question

Comment on the output of this C code?
#include <stdio.h>
    int main()
    {
        int a = 10;
        int **c -= &&a;
    }

a.

You cannot apply any arithmetic operand to a pointer

b.

We don’t have address of an address operator

c.

We have address of an address operator

d.

None of the mentioned

Posted under C Programming

Answer: (b).We don’t have address of an address operator

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Q. Comment on the output of this C code? #include <stdio.h> int main() { int a = 10; int **c -= &&a; }

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