Q. Which code for an alphabet (set of symbols) is generated by constructing a binary tree with nodes containing the symbols to be encoded and their probabilities of occurrence?

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Q. Trees are often used in implementing _________ and hence it is considered as prime application of trees.

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Q. The process of inserting a node in a binary search tree can be divided into how many steps?

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Q. The number of nodes in a complete binary tree of depth d (with root at depth 0) is

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Q. Every internal node in a B-tree of minimum degree 2 can have

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Q. In .............. the difference between the height of the left sub tree and height of right sub tree, for each node, is not more than one.

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Q. The in-order traversal of a binary tree is HFIEJGZ, and the post-order traversal of the same tree is HIFJZGE. What will be the total number of nodes in the left sub tree of the given tree? (It is NOT a search tree)

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Q. If the in-order and pre-order traversal of a binary tree are D,B,F,E,G,H,A,C and A,B,D,E,F,G,H,C respectively then the post-order traversal of that tree is

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Q. In a binary tree, the number of terminal or leaf nodes is 10. The number of nodes with two children is

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Q. The pre-order traversal of a binary-search tree is DBACFE. What is the post-order traversal?

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Q. What could be the worst case height of an AVL tree?

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Q. Which amongst the following cannot be a balance factor of any node of an AVL tree?

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Q. How many distinct binary search trees can be formed which contains the integers 1, 2, 3?

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Q. Level of any node of a tree is

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Q. In .............., it is possible to traverse a tree without using stacks either implicitly or explicitly.

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Q. The order of a B-Tree with 2, 3, 4 or 5 children in every internal node is

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Q. The number of nodes that have no successors in a complete binary tree of depth 4 is

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Q. One can make an exact replica of a Binary Search Tree by traversing it in ...............

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Q. A complete Binary Tree with 15 nodes contains ................. edges.

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Q. Visiting root node after visiting left and right sub-trees is called .............

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