Question
a.
S→S1S3, S1→aS1c |S2|λ, S2→aS2b|λ, S3→aS3b|S4| λ, S4→bS4c|λ
b.
S→S1S3, S1→aS1S2c |λ, S2→aS2b|λ, S3→aS3b|S4| λ, S4→bS4c|λ
c.
S→S1|S2, S1→aS1S2c|λ, S2→aS2b|λ, S3→aS3b|S4| λ, S4→bS4c|λ
d.
S→S1|S3, S1→aS1c |S2|λ, S2→aS2b|λ, S3→aS3b|S4| λ, S4→bS4c|λ
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Q. The context free grammar for language L = {a^nb^mc^k | k = |n - m|, n≥0,m≥0,k≥0} is
Krishnakumar.D : June 26, 2023
(D) Also incorect:
S-->S3
--->aS3b
---->aS4b
---->abS4cb
---->abcb (since S4--->lamba)
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