Q. From the given data below:

a b b a a b b a a b

which one of the following is not a word in the dictionary created by LZ-coding (the initial words are a, b)?

View solution

Q. The number of strings of length 4 that are generated by the regular expression (0+1+|2+3+)*, where | is an alternation character and {+, *} are quantification characters, is:

View solution

Q. Which of the following is FALSE ?

View solution

Q. The regular grammar for the language L = {a^nb^m | n + m is even} is given by

(A) S → S1 | S2
S1 → a S1 | A1
A1 → b A1 | λ
S2 → aaS2 | A2
A2 → b A2 | λ
(B) S → S1 | S2
S1 → a S1 | a A1
S2 → aa S2 | A2
A1 → bA1 | λ
A2 → bA2 | λ
(C) S → S1 | S2
S1 → aaa S1 | aA1
S2 → aaS2 | A2
A1 → bA1 | λ
A2 → bA2 | λ
(D) S → S1 | S2
S1 → aa S1 | A1
S2 → aaS2 | aA2
A1 → bbA1 | λ
A2 → bbA2 | b

View solution

Q. Let Σ = {a, b} and language L = {aa, bb}. Then, the complement of L is

View solution

Q. Consider the following identities for regular expressions :

(a) (r + s)* = (s + r)*
(b) (r*)* = r*
(c) (r* s*)* = (r + s)*

Which of the above identities are true ?

View solution

Q. Given the following two languages:

L1 = {uww^Rn | u, v, w ϵ {a, b}+}
L2 = {uwwR^n | u, v, w ϵ {a, b}+, |u| ≥ |v|}

Which of the following is correct ?

View solution

Q. Given a Turing Machine:

M = ({q0, q1}, {0, 1}, {0, 1, B}, δ, B, {q1})
Where δ is a transition function defined as
δ (q0, 0) = (q0, 0, R)
δ (q0, B) = (q1, B, R)

The language L(M) accepted by Turing machine is given as :

View solution

Q. Consider the following linear programming problem:

Max. z = 0.50x2 – 0.10x1
Subject to the constraints
2x1 + 5x2 ≤ 80
x1 + x2 ≤ 20
and x1, x2 ≥ 0

The total maximum profit (z) for the above problem is:

View solution

Q. The regular expression for the complement of the language L = {anbm|n≥4, m≤3} is:

View solution

Q. Consider the following two languages:

L1 = {0i1j | gcd(i,j)=1}
L2 is any subset of 0*.

Which of the following is correct?

View solution

Q. Let L be the language generated by regular expression 0*10* and accepted by the deterministic finite automata M. Consider the relation RM defined by M. As all states are reachable from the start state, RM has ................ equivalence classes.

View solution

Q. Let L = {0^n1^n | n≥0} be a context free language.
Which of the following is correct?

View solution

Q. Given a Turing Machine

M = ({q0,q1,q2,q3}, {a,b}, {a,b,B}, δ, B, {q3})

Where δ is a transition function defined as

δ(q0,a) = (q1,a,R)
δ(q1,b) = (q2,b,R)
δ(q2,a) = (q2,a,R)
δ(q2,b) = (q3,b,R)

The language L(M) accepted by the Turing Machine is given as:

View solution

Q. Match the following :

List - I                                                             List - II
(a) {a^n b^n|n > 0} is a deterministic                  (i) but not recursive language
context free language        
(b) The complement of {a^n b^n a^n|n > 0}         (ii) but not context free language
is a context free language
(c) {a^n b^n a^n} is context sensitive language (iii) but can not be accepted by a deterministic pushdown automation
(d) L is a recursive language                         (iv) but not regular

Codes :
     (a)   (b)   (c)   (d)

View solution

Q. The language of all non-null strings of a’s can be defined by a context free grammar as
follow :

S→a S|S a| a

The word a^3 can be generated by ................ different trees.

View solution

Q. The context free grammar given by

S→XYX
X→aX|bX|λ
Y→bbb

generates the language which is defined by regular expression:

View solution

Q. There are exactly ................ different finite automata with three states x, y and z over the alphabet {a, b} where x is always the start state.

View solution

Q. Given the following two languages :

L1={a^n b a^n|n>0}
L2={a^n b a^n b^n+1|n>0}

Which of the following is correct?

View solution

Q. Consider a language A defined over the alphabet ∑={0, 1} as A = {0^[n/2] 1^n: n >= 0} .
The expression [n/2] means the floor of n/2, or what you get by rounding n/2 down to the nearest integer.

Which of the following is not an example of a string in A ?

View solution