Discussion Forum
| Que. | A program P calls two subprograms P1 and P2. P1 can fail 50% times and P2 40% times. Then P can fail |
| a. | 50% |
| b. | 60% |
| c. | 10% |
| d. | 70% |
| Answer:70% |
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Prathima :(December 02, 2020)
Please explain clearly
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Program P fails when either P1 fails or P2 fails, i.e. failure of P1 + failure of P2. But this will also contain the case when both P1 and P2 fails at the same time, i.e. failure of P1 ∩ failure of P2, since this case will be already be counted on (P1+P2). Therefore, our final answer will be failure of P1 + failure of P2 - (failure of P1 ∩ failure of P2) = (50/100) + (40/100) -(50/100∗40/100) = (90/100) - (2000/10000) = (90/100) - (20/100) = (70/100) |
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