Q. X – = Y + 1 means

View solution

Q. The absorption law in Boolean algebra say that

View solution

Q. The number of 1’s present in the binary representation of

10 × 256 + 5 × 16 + 5 is

View solution

Q. The hexadecimal number equivalent to (1762.46)8 is

View solution

Q. (A + B)(AB)’ is equivalent to

View solution

Q. Encoding of data bits 0011 into 7-bit even Parity Hamming Code is

View solution

Q. What is decimal equivalent of BCD 11011.1100?

View solution

Q. The simplified form of the Boolean expression (X+Y+XY)(X+Z) is

View solution

Q. The answer of the operation (10111)2 * (1110)2 in hex equivalence is

View solution

Q. How many 1’s are present in the binary representation of

3 × 512 + 7 × 64 + 5 × 8 + 3

View solution

Q. The Boolean expression x’y’z+yz+xz is equivalent to:

View solution

Q. The octal equivalent of hexadecimal (A.B)16 is:

View solution

Q. The dual of the switching function x+yz is:

View solution

Q. The octal equivalent of the hexadecimal number FF is:

View solution

Q. The idempotent law in Boolean algebra says that:

View solution

Q. Simplified form of Boolean expression xy+(~x)z+yz is:

View solution

Q. In order to build a MOD-18 counter, the minimum number of flip flops needed is equal to:

View solution

Q. 2’s complement of -100 is:

View solution

Q. Which of the following expression remove hazard form: xy+zx’ ?

View solution

Q. How many 1’s are present in the binary representation of 15x256+5x16+3:

View solution