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Question

Consider the following languages.

L1 = {a^i b^j c^k | i = j, k ≥ 1}
L1 = {a^i b^j | j = 2i, i ≥ 0}

Which of the following is true?

a.

L1 is not a CFL but L2 is

b.

L1 ∩ L2 = ∅ and L1 is non-regular

c.

L1 ∪ L2 is not a CFL but L2 is

d.

There is a 4-state PDA that accepts L1, but there is no DPDA that accepts L2

Answer: (b).L1 ∩ L2 = ∅ and L1 is non-regular

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Q. Consider the following languages. L1 = {a^i b^j c^k | i = j, k ≥ 1} L1 = {a^i b^j | j = 2i, i ≥ 0} Which of the following is true?

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