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Question

Consider the binary relation:

S = {(x, y) | y = x+1 and x, y ∈ {0, 1, 2, ...}}

The reflexive transitive closure of S is

a.

{(x, y) | y > x and x, y ∈ {0, 1, 2, ... }}

b.

{(x, y) | y ≥ x and x, y ∈ {0, 1, 2, ... }}

c.

{(x, y) | y < x and x, y ∈ {0, 1, 2, ... }}

d.

{(x, y) | y ≤ x and x, y ∈ {0, 1, 2, ... }}

Answer: (b).{(x, y) | y ≥ x and x, y ∈ {0, 1, 2, ... }}

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Q. Consider the binary relation: S = {(x, y) | y = x+1 and x, y ∈ {0, 1, 2, ...}} The reflexive transitive closure of S is

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